A bullet of mass 0.1 kg moving horizontally with speed 400 m s -1 hits a wooden block of mass 3. 9 kg kept on a horizontal rough surface. The bullet gets embedded into the block and moves 20 m before coming to rest. The coefficient of friction between the block and the surface is_______.
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Verified by ExpertsThe correct answer is:
D
Let the mass of the bullet be m and mass of the block be M. It is given that V = 400 m s -1 . By conservation of momentum,
mV = (m + M)v
0.1 x 400 = (0.1 + 3.9)v
v = 10 ms -1 The force acting on the block
Using v'
2 - v 2 = -2aS
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